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Input:
fsolve(f(x+2)-f(x+1)-f(x)=0)
Write:
`fsolve(f(x+2)-f(x+1)-f(x)=0)`
Compute:
$$fsolve(f(x+2) - f(x+1) - f(x)=0)$$
Output:
$$fsolve(f(x+2) - f(x+1) - f(x)=0)== C_1\ fibonacci(x)+C_2\ lucas(x)$$
Result: $$C_1\ fibonacci(x)+C_2\ lucas(x)$$
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