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Input:
solve(mod(x^2-5x+7,2)=1)
Write:
`solve(mod(x^2-5x+7,2)=1)`
Compute:
$$solve(({x}^{2} - 5\ x+7)\ mod \ 2=1)$$
Output:
$$solve(({x}^{2} - 5\ x+7)\ mod \ 2=1)== 2\ n\ and\ 1+2\ n$$
Result: $$2\ n\ and\ 1+2\ n$$
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