Input:
solve(x^2-3x-2y-2=0,x,y)
Write:
`solve(x^2-3x-2y-2=0,x,y)`
Compute:
$$solve({x}^{2} - 3\ x - 2\ y - 2=0,x,y)$$
Output:
$$solve({x}^{2} - 3\ x - 2\ y - 2=0,x,y)== x=1-2\ n\ and\ y=\frac{-5}{2}+3\ n+\frac{1}{2}\ (1-4\ n+4\ {n}^{2})$$
Result: $$x=1-2\ n\ and\ y=\frac{-5}{2}+3\ n+\frac{1}{2}\ (1-4\ n+4\ {n}^{2})$$
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