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Input:
sum(1/k^2,k,1,oo)
Write:
`sum(1/k^2,k,1,oo)`
Compute:
$$\sum _{k=1} ^ {oo} \frac{1}{k^2}$$
Output:
$$\sum _{k=1} ^ {oo} \frac{1}{k^2}== \frac{1}{6}\ {\pi }^{2}$$
Result: $$\frac{1}{6}\ {\pi }^{2}$$
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